🎄 My adventjs commented solutions 🎄

adventjs.dev is a platform developed by where you can practice your JavaScript skills via challenges as an advent calendar. This repository contains my proposed solutions for all the challenges.

As I consider that if you are reading this you may be in the search of some help for succeeding on a challenge, all my solutions are described so you can understand what I implemented. There are some challenges with more than one solution (for example, an iterative and a functional one).

The solutions descriptions contain a title for identifying it, the calculated time complexity, an explanation step by step and, some author comments about it.

If you think you got into a better solution than the one I propose, please let me know, so I can include your solution (all the credits will be yours, of course).

Index of challenges

Day	Code + Description	Test
1	Contando ovejas para dormir	✅
2	¡Ayuda al elfo a listar los regalos!	✅
3	El Grinch quiere fastidiar la Navidad	✅
4	¡Es hora de poner la navidad en casa!	✅
5	Contando los días para los regalos	✅
6	Rematando los exámenes finales	✅
7	Buscando en el almacén...	✅
8	La locura de las criptomonedas	✅
9	Agrupando cosas automáticamente	✅
10	La máquina de cambio	✅
11	¿Vale la pena la tarjeta fidelidad del cine?	✅
12	La ruta perfecta para dejar los regalos	✅
13	Envuelve regalos con asteriscos	✅
14	En busca del reno perdido	✅
15	El salto perfecto	✅
16	Descifrando los números...	✅
17	La locura de enviar paquetes en esta época	✅
18	El sistema operativo de Santa Claus	✅
19	¿Qué deberíamos aprender en Platzi?	✅
20	¿Una carta de pangramas? ¡QUÉ!	✅
21	La ruta con los regalos	✅
22	¿Cuantos adornos necesita el árbol?	✅
23	¿Puedes reconfigurar las fábricas para no parar de crear regalos?	✅
24	-
25	-

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In game dev, generative art, and creative coding, sine is a ubiquitous function that is often used as a spring-like oscillator for a given parameter.

Feb 22, 2022

14 En busca del reno perdido

The difference between the sum of all of them and that they should add if they are all of them is the solution: Example: (1+2+3+4+5+6+7) - (1+2+3+0000+5+6+7) = 4 (The fourth is missing) 1/2*(7)(7+1)
export default function missingReindeer(ids) { return (1/2(ids.length)*(ids.length +1) )- ids.reduce((a,b)=>a+b) }

opened by crumblecoder 0
11-Cine

I think you can avoid using recursion with this formula:

export default function shouldBuyFidelity(times) { //https://www.wolframalpha.com/input/?i=250%2B%28-36+%28%283%2F4%29%5En+-+1%29%29 return times12 > 250+ (-36( Math.pow(3/4,times)-1)) }

I really appreciate this project. Thank you very much for sharing.

opened by crumblecoder 0

Personal repository for adventjs.dev

Related tags

Overview

🎄 My adventjs commented solutions 🎄

Index of challenges

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14 En busca del reno perdido

11-Cine

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